Question

Given cot theta = 7/8 , then evaluate (ii) 1+sin theta/ cos theta​

Answer 1

cot thita=7/8

means base is 7 and perpendicular is 8

H^2=P^2+B^2

H^2=8^2+7^2

H=√64+49

H=√113

1+sin thita/cos thita

1+(8/√113)/7/√113)

(√113+8/√113)/7/√113

√113+8/√113)×√113/7

√113+8/7

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