Question

given cot theta is equals to 7 by 8 then evaluate sin theta + cos theta​

Answer 1

Answer:

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Answer 2

Answer:

cot theta=7/8= b/p

now we have the evalute (1+ sin theta)

(1-sin theta)/(1+ sin theta)*(1- cos theta)

by paithagorash therom.

h=√p^2+b^2

h=√49+64=√113

sin theta p/h=81√113 and cos theta =b/h=7/√113

now (1+ sin theta)(1- sin theta)/(1+ cos theta)(1-cos theta)

=1- sin^2theta/1-cos^2theta

(1-(8√113)^2)/(1-√7/√113)^2)

=1-64/113/1-49-113

49/64

hence(1+sin theta) (1-sin theta)/(1+cos theta)(1-cos theta)

=49/64.

Step-by-step explanation:

hopeful for you....