given cotteta=7/8 , then evaluate 1) (1+sinteta)/costeta
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(1+ sinθ)÷cosθ=1/cosθ+tanθ=secθ+tanθ=√1+tan²θ +tanθ=√1+64/49 +8/7
=√113/7+8/7
=√113+8/7
tanθ=8/7
=√113/7+8/7
=√113+8/7
tanθ=8/7
mateen6020:
thank you..........:-) :-)
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