Question

Given cscθ∘=√32 and secθ∘=√33, how do you find sec(90∘−θ)?

Answer 1

Hey friend here is the solution for this question.....

$we \: know \: that \: \sec(90 - x) = \csc(x)$

so....

$\sec(90 - x) = \sqrt{32}$

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