Given d=5 ,S9=75,find a and a9
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here ur ans
d = 5 ,
S9 = 75
S9 = n/2[2a+(n-1) d
75 = 9/2[2a+(9-1) 5
(75*2) /9 = 2a+20
150/9 = 2a +20
150/9 -20 = 2a
(150-180) /9 = 2a
-10/9 = 2a
-10/9*2 = a
a = -5/9
a9 = a+8d
= -5/9 + 8 (5)
= -5/9 +45
= (-5+405) /9
= 400/9
hope it correct to u
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