Question

Given data of a simple curve: Azimuth from south of line AB = 275°, Azimuth from south of line BC 323°, R = 327.4 m, sta PC = 1+073

Answer 1

Step-by-step explanation:

A simple circular curve connects two straights (AB & BC) intersected at point B. Station 2+090. If the azimuth of line BC is 120" and the coordinates of PC and B are (100, 100) m and (200, 200) m respectively. Determine: Degree of the Curve (use Are Basis) D 75 O Angle of Intersection 105 Point of curvature PC Station 2 + 858.58 Point of tangency PT Station 2 + 099.83 Tangent (PC to PI or PI to PT) T 141.42 m Radius of simple curve R 184.30 m Length of chord from PC to PT L 224.39 Length of curve from PC to PT LC 241.25 m External distance E 232.31 m Middle ordinate or mid ordinate mm 38.09 m