Question

Given defective percentage find out probability that selected two bulbs are defective

Answer 1

Answer:

Step-by-step explanation:

Probability of an item being defective (p) = .05. Hence, probability of an item being non-defective (q) = 1 - .05 = .95. Now, Probability { getting more than 4 defective items in a sample of 200 items} = 1 - Pr { getting 4 or less defective items}.

Pr{ getting 4 or less defective items} = 200C0 * p^0 * q^200 + 200C1 * p * q^199 + 200C2 * p^2 * q^198 + …..+ 200C4 * p^4 * q^0

Find this probability (P) putting the value of p and q. Hence, the required probability is 1 - P.

JUST AN EXAMPLE DO IT URSELF