Question

Given : EB = DB,AE = BC,∠A=∠C=90° So, ΔABE≅ΔCDB

Answer 1

HOLA

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Given -- EB = DB , AE = BC

Whereas angle A = C = 90

Hence , A = C

In both the triangle angles and the sides are equal

Hence we conclude

∆ ABE = ∆ CDB

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HOPE U UNDERSTAND ☺☺☺☺

Answer 2

Given : EB = DB

AE = BC given

Angle A = Angle C = 90°

so triangle ABE is congruent to triangle CDB by RHS criterion

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