Math, asked by mayurrajput051998, 1 month ago

Given equations (5xy+3xz+2y+50z)dx+(2yz+3xz+5z)dy=0
2 points
M=5xy-3xz+2y+50z and N=2yz+3xz+5z
M=5xy+3xz+2y+50z and N=2yz-3xz+5z
M=5xy+3xz+2y+50z and N= 2yz+3xz+5z
M=-5xy+3xz+2y-50z and N= 2yz+3xz+5z​

Answers

Answered by yarya6654
1

M=5xy-3xz+2y+50z and N=2yz+3xz+5z

M=5xy+3xz+2y+50z and N=2yz-3xz+5z

M=5xy+3xz+2y+50z and N= 2yz+3xz+5z

M=-5xy+3xz+2y-50z and N= 2yz+3xz+5z

Step-by-step explanation:

Given X put in Y and Z

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