Given: (ES) bisects (FR) ∠F≅∠R
Prove: (EF) ≅ (SR)
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ES=ED+DS
FR=FD+DR
ED=DS(GIVEN)
FD=DR(GIVEN)
ANGLE EDF=ANGLE SDR(by SAS)
Hense,(EF) ≅ (SR) (by C.P.C.T.C)
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