Given f(0) = – 2, f ′(0) = 3. Find h′(0), where h(x) = xf(x).
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C
3
Given:-f(0)=2,f(1)=3
f(x+2)=2f(0)−f(x+1)
Put,x=0
f(2)=2f(0)−f(1)
f(2)=4−3=1
f(2)=2f(0)−f(2+1)
f(3)=2f(0)−f(2)
f(3)=4−1
f(3)=3
Put,x=2
f(4)=2f(2)−3
f(4)=1
Put,x=3
f(5)=2f(3)−f(3+1)
f(5)=4−1=3
Answered by
1
Step-by-step explanation:
hope this will help and sorry for those rough work
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