Math, asked by nwashingtonmarshall, 9 months ago

given f(x) = 1/3 (4 - x)^2, what is the value of f(16)?

Answers

Answered by sunita1986rajwade
3

Answer:

putting the value of x in f (x) is 16

f(16) = 1/2(4-x)/2

= 1/3×-12/2

= -12/6

= -2ans

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