Math, asked by heidi2mimi, 9 months ago

Given f(x)= 1/3(4-x)^2 , what is the value of f(16) Please help!!

Answers

Answered by BesimpleBesmart
9

 \boxed{answer} \\  \\ when \: ever \: you \: see \: an \: x \: on \: the \\ right \: put \: a \: 16 \: that \: whatf(16) \\ means. \\  \\ f(16) =  \frac{1}{3}  \: (4 -  {16})^{2}  \\  \\ f(16) =  \frac{1}{3} ( -  {12})^{2}  \\  \\ f(16) =  \frac{1}{3} (144) \\  \\ f(16) = 48 \\  \\ \color{red}[is \: your \: answer]

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