Question

Given f(x)=2x-x2 find f(1)

Answer 1

Answer:

2(1)-(1)^2=2-1=1

Step-by-step explanation:

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Answer 2

Concept: When a variable in an equation like the quadratic equation, cubic equation, etc. has only non-negative integer powers or only positive integer exponents, the function is said to be polynomial. One polynomial with an exponent of 1 is 2x+5, for instance. Depending on its degree, a polynomial function is also stated as a polynomial or polynomial expression. The highest power contained in a polynomial is called its degree. Depending on the degree of the polynomial, there are many types of polynomial functions. The most typical kinds are:

P(x) = 0; where all ai's are zero, I = 0, 1, 2, 3,..., n

Constant polynomial function: P(x) = a = $ax^{0}$

Zero polynomial function: P(x) = 0

P(x) = ax + b is a linear polynomial function.

P(x) = $ax^{2} + bx + c$ is a quadratic polynomial function.

Function of a Cubic Polynomial: $ax^{3} + bx^{2} + cx + d$

Function of a Quartic Polynomial: $ax^{4} + bx^{3} + cx^{2} + dx + e$

Given: $f(x) = 2x - x^{2}$

To find: f(1)

Solution: In order to find f(1), substitute 1 at the place of x in the function $f(x) = 2x - x^{2}$

$f(1) = 2(1) * 1^{2}$

$f(1) = 2 * 1\\f(1) = 2$

Hence, f(1) = 2

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