given f(x) = 3x^3-5x^2-10 and g(x)=x^3+5x- are two polynomials .if f(x) and g(x) both are divided by (x-2) then the obtained remainders are r1 and r2 respectively . the value of (r1+r2 -r1 r2) is
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Given:
f(x) = 3x³ - 5x² - 10, g(x) = x³ + 5x - 3
Both f(x) and g(x) are divided by (x - 2)
To find:
The value of, r₁ + r₂ - r₁ r₂
Solution:
f(x) = 3x³ – 5x² – 10
Dividing by x - 2, we get,
x = 2
remainder = 3(2)³ - 5(2)² - 10 = 24 - 20 - 10 = - 6
r₁ = -6
g(x) = x³+ 5x - 3
Dividing by x - 2, we get,
x = 2
remainder = (2)³ - 5(2) - 3 = 8 - 10 - 3 = - 5
r₂ = - 5
Now consider,
r₁ + r₂ - r₁ r₂
= -6 - 5 - (-6)(-5)
= -11 - 30
= - 41
∴ r₁ + r₂ - r₁ r₂ = - 41
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