Given f(x)=3x^4 - 5x^3 + x^2 +8 find f (-1/2) ,f (1) ,f (-1) and f (-1/3)
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if f(x)=3x⁴-5x³+x²+8
f(-1/2)= 3×(-1/2)⁴+5×(-1/2)³+(-1/2)²+8
= 3×1/16-5×(-1/8)+1/4+8
=3/16+5/8+1/4+8
=(3+10+4+128)/16
=145/16
f(1)=3×1-5×1+1+8
=3-5+1+8
=7
f(-1)=3×1-5×(-1)+1+8
=3+5+1+8
=17
f(-1/3)=3×(-1/3)⁴-5×(-1/3)³+(-1/3)²+8
=1/27+5/27-1/9+8
(= 1+5-3+216)/27
219/27=8.1
hope dis help
f(-1/2)= 3×(-1/2)⁴+5×(-1/2)³+(-1/2)²+8
= 3×1/16-5×(-1/8)+1/4+8
=3/16+5/8+1/4+8
=(3+10+4+128)/16
=145/16
f(1)=3×1-5×1+1+8
=3-5+1+8
=7
f(-1)=3×1-5×(-1)+1+8
=3+5+1+8
=17
f(-1/3)=3×(-1/3)⁴-5×(-1/3)³+(-1/3)²+8
=1/27+5/27-1/9+8
(= 1+5-3+216)/27
219/27=8.1
hope dis help
ritikajaiswal1:
thanks dd
that's my pleasure.☺
but your answer is wrong in last step (-1/3) ka whole square= 1/9 aayega but aapne -1/9 likha hai ok please check
hmm but i can't edit it till now u can report it
if u want
then someone can give u the right ans
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please mark it as a brainiest answer
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