Question

Given f(x) = (x-4)(x+3)+4, when f(x) is divided by (x-k), the remainder is k. Find k.

Answer 1

Answer:

wait a minute I will give you the ans

Answer 2

$k^2-k-8$Answer:

4 and -2

Step-by-step explanation:

f(x) = (x-4)(x+3)+4

     = $x^2-4x+3x-12+4$

f(x) = $x^{2}- x-8$

Remainder = f(k)

f(k) = $k^2-k-8$

Substitute the given remainder = k

k =  $k^2-k-8$

$k^2-2k-8$ = 0

(k-4)(k+2) = 0

k = 4 and k = -2