Given, f(x) = x²-3x-2. Find f[f(x)]
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Answer:
We have, f(x) = x^2-3x-2
So, f[f(x)] = f(x^2 - 3x - 2)
= (x^2 - 3x - 2)^2 -3(x^2-3x-2) -2
= x^4 - 6x^3 + 2x^2 + 21x + 8
Step-by-step explanation:
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