Question

given figure ABCDE is a pentagonal park in which DE=DC , AB=BC=CE=EA=25m and its

total height is 41 m . Find the area of the park.



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Answer 1

Answer:

825cm

Step-by-step explanation:

Height of triangle =41−25=16cm

Area of park = area of square ABCE+ area of ΔDEC

=25×25+ 21×25×16

=625+200

=825cm

Answer 2

Given:-

• DE = DC, AB = BC = CE = EA = 25

• Its total height is 41m

To find:-

• The area of the park

Solution:-

Height of triangle = 41 - 25 = 16cm

Area of park = Area of square ABCE + Area of triangle DEC

$\implies$ 25 × 15 + 1/2 × 25 × 16

$\implies$ 625 + 200

$\implies$ 825cm²

Therefore, The area of park = 825cm²