Question

given figure shows a hollow plastic pipe of thickness 1 cm and length 5 metre the mass of the pipe is 21.7 8 kg and the density of the pipe used in pipe is 0.99 gram per centimetre cube what is the outer diameter of the pipe​

Answer 1

Answer:

Let external diameter be d2 and internal be d1

⇒d2=8cm & d1=8−1−1=6cm

Therefore, r1=3cm & r2=4cm

Volume of hollow cylindrical pipe=π(r22−r12)×h

=722((4)2−(3)2)×21

=722×7×21

=462cm3

∴Weight of the pipe=8×462=3696g=3.696kg