Given figure shows the observation of a point c from point a the angle of depression from A is ?
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tan A= BC/AB
=2√3/2
=√3
So tan A=√3
Tan A =tan60
A=60°
Angle sum property
Angle A+ ANGLE B+ ANGLE C= 180°
60+90+ ANGLE C=180
angle c = 180-60-90
Angle C =30°
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Answer:
the answer is 30
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