Given figure shows two long parallel wires P & Q separated by a distance of 4.0 cm and carrying equal currents of 100 A along opposite directions. Find the magnitude of the magnetic field B at the points A1, A2, A3 and A4.
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Answers
Answer:
Let the tow wires be positioned at O & P
R=OA,=
(0.02)
2
+(0.02)
2
=
8×10
−4
=2.828×10
−2
m
a)
B
due to Q, at A
1
=
2π×0.02
4π×10
−7
×10
=1×10
−4
T (⊥r towards up the line)
B
due to P, at A
1
=
2π×0.06
4π×10
−7
×10
=0.33×10
−4
T (⊥r towards down the line)
net
B
=1×10
−4
−0.33×10
−4
=0.67×10
−4
T
b)
B
due to O at A
2
=
0.01
2×10
−7
×10
=2×10
−4
T ⊥r down the line
B
due to P at A
2
=
0.03
2×10
−7
×10
=0.67×10
−4
T ⊥r down the line
net
B
at A
2
=2×10
−4
+0.67×10
−4
=2.67×10
−4
T
c)
B
at A
3
due to O=1×10
−4
T ⊥r towards down the line
B
at A
3
due to P=1×10
−4
T ⊥r towards down the line
Net
B
at A
3
=2×10
−4
T
d)
B
at A
4
due to O=
2.828×10
−2
2×10
−7
×10
=0.7×10
−4
T towards SE
B
at A
4
due to P=0.7×10
−4
T towards SW
Net
B
=
(0.7×10
−4
)
2
+(0..7×10
−4
)
2
=0.989×10
−4
≈1×10
−4
T
Explanation:
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Answer:
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