Question

given figure, ST ॥ RQ, PS = 3 cm and SR = 4 cm. Find the ratio of the area of ΔPST to the area of ΔPRQ.

Answer 1

PS/ SR = 3/ 4 , SO we cn also write it as
SR/PS = 4/ 3

SR/ PS +1 = 4/3 + 1
SR+PS / PS = 4+3/3
PR/PS = 7/ 3
Area of tri PST / Area of tri PRQ =
$7 {}^{2} \div 3 {}^{2}$
i.e. 49 ÷ 9 or
49 : 9
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Answer 2

Answer:

9:49

Step-by-step explanation:

Given

ST || RQ

PS= 3 cm

SR = 4cm

Proof :--

ar(∆PST) /ar(∆PRQ) = (PS)²/(PR)²

ar(∆PST) /ar(∆PRQ) = 3²/(PS+SR)²

ar(∆PST) /ar(∆PRQ) = 9/(3+4)²= 9/7² = 9/49

Hence, the required ratio ar(∆PST) :ar(∆PRQ) = 9:49