Physics, asked by anant247040, 1 month ago

Given G in cgs is 6.67 x 10 -8 dyne cm² / g², find its value in mks

Answers

Answered by acharyadipesh19
0

soln,

Given,

G=6.67*10^{-8}dyne cm^2/g^2

now,

converting:                

1) dyne into Newton,          2) cm^2 into m^2

   100000dyne=1 N            (100 cm)^2=1 m^2

    or, 10^5 dyne= 1 N           or, 10000 cm^2\\ =10^4 cm^2= 1 m^2

   :. 1 dyne = 10^{-5}  N             :. 1cm^2= 10^{-4} m^2

_________________________________________________________

3) g^2 into Kg^2   \\

(1000 g)^2 = 1000000 g^2= 10^6 g^2 = 1 kg^2

:. 1 g^2 =  10^{-6}  kg^2

_________________________________________________________

Now, through the given, and above derivation replacing dynes into N, cm into m and g into kg for  value of G in MKS system of units,

G =6.67*10^{-8} dyne cm^2/g^2

  = \frac{6.67*10^{-8}* 1 dyne*1cm^2}{1g^2}

 =   \frac{6.67*10^{-8}* 10^{-5} N*10^{-4}m^2}{10^-6 kg^2}

 = \frac{6.67*10^{(-8-5-4)} Nm^2}{10^{-6} Kg^2}

 = 6.67*10^{-17} Nm^2*10^6 /kg^2

 = 6.67*10^{(-17+6)}Nm^2/ kg^2\\

 =6.67*10^{-11} Nm^2/kg^2                                    

Similar questions