given graph(for a projectile motion) shows variation of vertical velocity (y-component of vector) with time. Then the maximum height of projectile is[g =10m/s^2]
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Answered by
69
Answer:
Answer is option c i.e. 3 m
Explanation:
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34
Answer:
5m will be the height.
Explanation:
Since, we know that u is the initial velocity of the body hence, we use the newtons laws of motion to get the value of initial velocity u= gt since we know the value of g is 10 and time t is 1 and also final velocity v is 0 m/s.
So, u = 10 m/s. Hence, again applying Newton's laws of motion we will get that height h = u^2/2a. Hence, on applying the values of u as 10 and a as 10 we will get the value of height as 5m.
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