Question

given h(x)=-2(x²-2x+4) what is the value of h(-3)

Answer 1

Answer:

given that h(x) = 2( x2_2x+4)

then h(_3)=2( (_3)2 _2(_3)+4)

h(_3)= 2(9+6+4)

h(_3)=2(19)

h(_3)=38