Question

Given h(x). Determine the value of -2h(-1)+h(3)-4h(2)?
MAKE SURE YOU ANSWER IT OR I WILL NOT MARK YOU AS BRAINLIEST
I WANT TO SEE A SOLUTION!​

Answer 1

Given :

$\sf h(x) = \begin{cases} \sf{\sqrt{3 - x}} & \sf x \leq -1 \\ \sf x^{2} - 5x + 2 & \sf -1 < x \leq 2 \\ \sf 7x - 9 & \sf x > 2 \end{cases}$

To Find :

-2 h(-1) + h(3) - 4h(2)

Solution :

Let us find the values of h(x) ,

★══════════════════════★

h(-1)

$\to \sf \sqrt{3-(-1)}$

$\to \sqrt{4}$

$\to 2$

h(3)

$\to 7(3)-9$

$\to 21-9$

$\to 12$

h(2)

$\to (2)^2-5(2)+2$

$\to 4-10+2$

$\to 6-10$

$\to -4$

★══════════════════════★

$:\implies \textsf{\textbf{-2h(-1)\ +\ h(3)\ -\ 4h(2)}}\ \; \pink{\bigstar}$

$:\implies \sf -2(2)+(12)-4(-4)$

$:\implies \sf -4+12+16$

$:\implies \sf -4+28$

$:\implies \textsf{\textbf{24}}\ \; \green{\bigstar}$