given HCF(12576,4052)=4 ;find LCM(12576,4052)
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2
Step-by-step explanation:
The remainder has now become zero, so procedure stops. Since the divisor at this stage is 4, the HCF of 12576 and 4052 is 4
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4
LCM= 12739488
Step-by-step explanation:
Given:- first number= 12576 , second number= 4052 , HCF = 4 and LCM = ?
We know that,
first number× second number= LCM×HCF
12576×4052= LCM× 4
12576×4052/4= LCM
LCM = 12739488
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