Question

Given HCF( 3m, 161) = 23 and LCM (3m, 161) = 1449 then the value of m is

Answer 1

Answer:

m = 207

Step-by-step explanation:

Given :

HCF( 3m, 161) = 23 and

LCM (3m, 161) = 1449

Solution :

We know that,

LCM x HCF = PRODUCT OF THE NUMBERS

So, 23 x 1449 = 3m x 161

or, 33327 = 483m

or, m = 33327/483

so, m = 207

So, the two numbers are (3m, 161) = (621, 161)

For m being 207.

Answer 2

Answer:

Given:

HCF of (3m, 161) is 23 and LCM of (3m, 161) is 1449.

To Find:

We need to find the value of m.

Solution:

As we know, the product of HCF and LCM is equal to the product of numbers. That is,

HCF × LCM = Product of numbers

=> 23 × 1449 = 3m × 161

=> 33327 = 483m

=> 33327/483 = m

=> 207 = m

or m = 207

3m = 3 × 207 = 621

So, the numbers are (621, 161)

Hence value of m is 207.