Math, asked by saiprashanth731, 3 months ago


Given HCF of A and B is 48, HCF of C and D is 36. What is the HCF of A,B,C and D
48
36
12
24​

Answers

Answered by purvi22082001
3

Step-by-step explanation:

Given HCF of A and B is 24

Factors = 2×2×2×3

C and D HCF is 36

factors = 2×2×3×3

thus combined HCF of A , B ,C ,D is 2×2×3 = 12

( by taking common )

Answered by Anonymous
0

Given:

HCF of A and B = 48

HCF of C and D = 36

To Find:

The HCF of A,B,C and D

Solution:

HCF of A and B is = 48

Thus,

It's factors = 2 × 2 × 2 × 2 × 3

Similarly,

HCF of C and D HCF is = 36

It's Factors = 2 × 2 × 3 × 3

Therefore,

The combined HCF of A , B ,C ,D will be -

= 2 × 2 × 3

= 12

Answer: The HCF of A,B,C and D is 12.

Similar questions