Question

Given identities Find the value of
${101}^{3}$
​

Answer 1

Hope it helps.................

Answer 2

$\huge\mathbb{SOLUTION:-}$

identity used :-

$\boxed{\sf{(a+b){}^{3}=a{}^{3}+b{}^{3}+3ab(a+b)}}$

Now

$\bf\underline{\red{\:\:\:\:A.T.Q\:\:\:\:}}$

we can write this in the form of

$\sf\bullet (100+1){}^{3}$

$\sf\implies (100+1){}^{3}\\ \\ \sf\implies (100){}^{3}+(1){}^{3}+3\times 100\times 1(100+1)\\ \\ \sf\implies 1000000+1+300\times 101\\ \\ \sf\implies 1000001+30300\\ \\ \sf\implies 1030301$

$\boxed{\sf{(101){}^{3}=1030301}}$