Given: In ∆ABC;AC=BC,CD parallel to BA and angle DCA =55 DEGREES .. Calculate: AngleACB
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As BAllCD , Angle ACD=Angle CAB=55°( Alternate Interior Angles
Also,Angle CAB=Angle ACB =55°(if there are two equal sides, then the angles opposite to them Will be equal)
Hope it helps you...
Please mark as brainliest answer!!!
Also,Angle CAB=Angle ACB =55°(if there are two equal sides, then the angles opposite to them Will be equal)
Hope it helps you...
Please mark as brainliest answer!!!
Anonymous:
plz mark as brainliest
thanks
Answered by
1
ecd is a straight line
cd is parallel to ab
and cb is a transversal
therefore angle DCB = ANGLE ABC =55 degree
angle ECA = angle CAB = 180-55 = 125 degree
angle abc+ acb+ cab = 180 degrees
125+ 55 -x = 180
cd is parallel to ab
and cb is a transversal
therefore angle DCB = ANGLE ABC =55 degree
angle ECA = angle CAB = 180-55 = 125 degree
angle abc+ acb+ cab = 180 degrees
125+ 55 -x = 180
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