Question

Given : in ∆ABC,∆B=90° if 15 cot A =8, find sin A and sec A​

Answer 1

Answer:

SinA =15/17

SecA =8/17

For the angle A opposite side is 15, adjacent side is 8 and hypotenuse is 17.

Answer 2

Answer:

Step-by-step explanation:

15 cot A =8

cotA=8/15 =base/height

so let base=8 and height=15

H=√(64+225)=√289=17

Thus

sinA=height/H=15/19

and secA=H/base=17/8

NB: H=> Hypotenuse