Question

Given: In quadrilateral ABCD angle C=64°angle D=angle C- 8° ; angle A=5(a+2)° and angle B = 2(2a+7)° . Calculate angle A
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Answer 1

Answer:

Step-by-step explanation:

9a+24=180

a=156/9

a=52

A=54*5

A=270

Answer 2

Answer:

Angle A=130°

Step-by-step explanation:

the sum of all angles in a quadrilateral is 360°

Angle A=5(a+2)

Angle B=2(2a+7)

Angle C=64°

Angle D=64-8

=56°

Sum of angles =360°

5(a+2)+2(2a+7)+64°+56°=360°

5(a+2)+2(2a+7)+120°=360°

5(a+2)+2(2a+7)=360°-120°

5(a+2)+2(2a+7)=240°

5a+10°+4a+14°=240°

9a+24°=240°

9a=240°-24°

9a=216°

a=216°/9

a=24°

Angle A=5(a+2)

=5(24+2)

=5(26)

=130°

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