Question

Given in the figure from an external
point P, a tangent PT and a line
segment PAB is drawn to a circle with
centre O. ON is perpendicular on the
chord AB. Prove that:
() PA. PB = PN^2 - AN^2
(i) PN^2- AN^2 = OP^2- OT^2
(iii) PA.PB = PT?​

Answer 1

Answer:

PN^2- AN^2 = OP^2- OT^2mm....

PA. PB = PN^2 - AN^2

Step-by-step explanation:

.......

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