Given : In trapezium PQRS,
side PQ || side SR, AR = 5AP,
AS = 5AQ then prove that,
SR = 5PQ
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Answer:
5PQ
Step-by-step explanation:
A trapezium PQRS is drawn in such a way that PQ || RS , AR = 5AP and AS = 5AQ
See In figure, ∵ PQ || RS
∴ ∠PQA = ∠ASR
∠QPA = ∠ARS
And also ∠PAQ = ∠SAR
From A - A - A similarity rule,
∆APQ ~ ∆ARS
∴ PQ/RS = AP/AR = AQ/AS
Given, AR = 5AP so,
PQ/RS = AP/5AP = 1/5
⇒PQ = RS/5
⇒RS = 5PQ or, SR = 5PQ
Hence, proved\bf{SR=5PQ}SR=5PQ
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