Question

Given: In triangle DEF, DE² + EF²= DF², triangle PQR is constructed such that PQ = DE, QR = EF and angle Q= 90°.
Prove that: triangle DEF is a right-angled triangle.​

Answer 1

Step-by-step explanation:

Given:  PR=EF, QR=DE and PQ=FD

Now, In △PRQ and △DEF

PR=EF

QR=DE

PQ=FD

Thus, △PQR≅△FDE (SSS rule).