Question

. Given in triangle PQR angle Q=90, Sin P = 3/5 Find:Sec P X Cot P​

Answer 1

Answer:

5/3

please mark this answer as brainliest.

Answer 2

answer is 5/3

Step-by-step explanation:

In triangle PQR

Sinp=3/5

by pythagoers theoem

Base = 4

secP = H/ B=5/4

Cotp= B/ P=4/3

So,

secPXCotP= 5/4.4/3

= 5/3