Question

Given initial velocity of 25m/s and flight angle of 25 degrees, find the range of the projectile?

Answer 1

Given

Initial velocity = 25 m/s

Flight angle = 25°

To Find

Range of the projectile

Solution

We know that

$\sf \longrightarrow R=\dfrac{u^{2} \sin 2 \theta}{g}$

Here

• R = range
• u = initial velocity
• θ = angle of flight
• g = acceleration due to gravity

According to the question

We are asked to find the rage of the projectile

Therefore

We must find "R"

Given that

Initial velocity = 25 m/s

Flight angle = 25°

Hence

• u = 25 m/s
• θ = 25°

We know that

• g = 10 m/s²

Substituting the values

We get

$\sf \longrightarrow R=\dfrac{25^{2} \times \sin (2 \times 25)}{10} \ m$

$\sf \longrightarrow R=\dfrac{625 \times \sin (50)}{10} \ m$

$\sf \longrightarrow R=\dfrac{625 \times 0.76}{10} \ m$

$\sf \longrightarrow R=\dfrac{478.7}{10} \ m$

Therefore

$\sf \longrightarrow R=47.87 \ m$

Hence

Range of the projectile = 47.87 m