Question

Given is the following code fragment :
if(a==0)
s. o. pln("0");

if(a==1)
s. o. pln("1");

if(a==2)
s. o. pln("2");

if(a==3)
s. o. pln("3");

WRITE AN ALTERNATIVE CODE (USING IF)THAT SAVES ON NUMBER OF COMPARISONS.

Answer 1

I think the answer is if ( 887)