Math, asked by cliffhurst520, 1 month ago

Given is Triangle ABC right-angled at B, write all the six trigonometric ratios

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Answers

Answered by kushwaneha
0

Answer:

We have,

sinA=

Hypotenuse

Perpendicular

=

5

3

So, we draw a right triangle right angled at B such that

Perpendicular =BC=3 unit and, Hypotenuse =AC=5 units.

By Pythagoras theorem, we have

AC

2

=AB

2

+BC

2

⇒5

2

=AB

2

+3

2

⇒AB

2

=25−9=16

⇒AB=

16

=4

When we consider the trigonometric ratios of ∠ C , we have

Base =BC=3, Perpendicular =AB=4, and Hypotenuse =AC=4

∴sinC=

Hypotenuse

Perpendicular

=

5

4

cosC=

Hypotenuse

Base

=

5

3

tanC=

Base

Perpendicular

=

3

4

cosecC=

Perpendicular

Hypotenuse

=

4

5

secC=

Base

Hypotenuse

=

3

5

and,

cotC=

Perpendicular

Base

=

4

3

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