Given, K., of silver chromate is 4 x 10". The silver ion concentration :
saturated silver chromate solution should be
(a) 10-⁴M
(b) 2 x 10-⁴M
(c) 2 x 10-⁶M
(d) 4x 10-⁶M
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Answer:
The equilibrium is:
Ag2CrO4⇌2Ag++CrO42−
On the basis of this equation, the concentration of CrO42− ion will be half of the concentration of Ag+ ions.
Thus, [Ag+]=4×10−4M
and [CrO42−]=2×10−4M
Ksp=[Ag+]2[CrO42−] =32×10−12
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