Given kp= 3cm, area of trianglekop= 2cm^2 and area of opml= 16cm^2, find the length of pm
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Answer:
plzz give the figure
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Step-by-step explanation:
KOP is similar to KLM
Area of KOP=2cm²
Area of KLM=16+8 cm²=18 cm²
Area of KOP/Area of KLM=(l1/l2)²
2/18=(3/3+x)²
(3+x)²=18×9÷2
(3+x)²=81
3+x=9
x=9-3
x=6 cm
PM is 6 cm
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