Question

Given kp= 3cm, area of trianglekop= 2cm^2 and area of opml= 16cm^2, find the length of pm

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

KOP is similar to KLM

Area of KOP=2cm²

Area of KLM=16+8 cm²=18 cm²

Area of KOP/Area of KLM=(l1/l2)²

2/18=(3/3+x)²

(3+x)²=18×9÷2

(3+x)²=81

3+x=9

x=9-3

x=6 cm

PM is 6 cm