Question

Given L=12 cm,B=9 cm.find the perimeter and area of rectangle

Answer 1

Answer:

$area \: of \: rectangle \: = l \times b \\ = 12 \times 9 \\ = 108 \\ perimeter \: of \: rectangle = 2 \times (l + b) \\ = 2 \times (12 + 9) \\ = 2 \times 21 \\ = 42$

Answer 2

Answer:

perimeter 2(l+b)

2(12+9)

24+18

42cm answer

Area l*b

12*9

108cm^2

Step-by-step explanation:

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