Math, asked by Ssauravs2527, 1 year ago

Given : Length of the room = 12 m Let the Breadth and the height of the room be 'b' m and 'h' m respectively. area of the floor = L × B = 12 m × b Area of the floor = 12b m² Cost of matting the floor = 0.85/m² ∴ Total cost of matting the floor = 0.85 × 12b ⇒ Rs. 0.85 × 12b = Rs. 91.80 10.2b = 91.8 b = 91.8/10.2 Breadth of the room = 9 meter So, the area of the walls of the room = 2h(L + B) = 2h(12 + 9) Area of the walls = 42h m² Cost of preparing the walls = Rs, 1.35/m² Total cost of preparing the walls = 1.35 × 42h ⇒ Rs. 1.35 × 42h = Rs. 340.2 56.7h = 340.2 h = 340.2/56.7 Height of the room = 6 meter In this how did 10.2 and 56.7 came

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Answered by Dhonish
0
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