Question

Given: Line AC and line AB are tangents
To prove that AM = 1/2 (Perimeter of triangle ABC)




Figure is provided..​

Answer 1

Step-by-step explanation:

AM=AN ( tangents from a common point are equal)

BM=BP

CP=CN

Perimeter ABC = AB + AC + BC

= AM-BM+AN-CN+BP+CN

= AM-BP+AM-CN+BP+CN

= AM+AM = 2AM

Therefore, Perimeter ABC = 2AM

AM = 1/2 (Perimeter triangle ABC)