given log 2=0.3010, log 3=0.4771 and log 5=0.6990: find : log 216 to the base 5
Answers
Answer:
Given that log 2 = 0.3010 and log 3 = 0.4771, the value of log5512 is equal to: (a) 2.870 (b) 2.967 (c) 3.876 (d) 3.912?
Let us use properties of logarithms by converting the given expression to the base 10.
If log 2 = 0.3010 and log 3 = 0.4771, the value of log5 256 is:?
If log 2 = 0.3010 and log 3 = 0.4771,what is the value of log5 512 is?
How do you solve this question, given that log 3=0.0.4771, log 5=0.6990 and log 2=0.3010, without using a calculator or mathematical table, evaluate log 0.243 (all are to base 10)?
If log 2=0.401 and log 3=0.477, what is log 0.54?
If log 2=0.3010, what is the value of log 500?
512=2^9
So log(512)to the base 5=log(2^9)/log5
=>9log2/log5
Now we will find the value of log5=log10/2=log10-log2=1–0.301=0.699
(It is very general to use log10=1)
Now we can easily calculate the value of log 512 to the base 5=9(0.301)/(0.699)
=3.8755
You've to use these log properties here :
log (m/n) = log (m) - log (n).
log m^n = n* log (m).
Answer:
If log 2 = 0.3010 and log 3 = 0.4771, the value of log5 256 is:?
If log 2 = 0.3010 and log 3 = 0.4771,what is the value of log5 512 is?
How do you solve this question, given that log 3=0.0.4771, log 5=0.6990 and log 2=0.3010, without using a calculator or mathematical table, evaluate log 0.243 (all are to base 10)?
If log 2=0.401 and log 3=0.477, what is log 0.54?
If log 2=0.3010, what is the value of log 500?
512=2^9
So log(512)to the base 5=log(2^9)/log5
=>9log2/log5
Now we will find the value of log5=log10/2=log10-log2=1–0.301=0.699
(It is very general to use log10=1)
Now we can easily calculate the value of log 512 to the base 5=9(0.301)/(0.699)
=3.8755
You've to use these log properties here :
log (m/n) = log (m) - log (n) .
log m^n = n* log (m) .
Explanation: