Given , log 5 = 0.699 and 1000^x = 5 .
Find 'x'
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Step-by-step explanation:
log to the Base 10
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Step-by-step explanation:
1000^x = 5
taking "log" of both side
=> log(1000^x) = log5
{logA^B = B.log(A) }
=> x.log(1000) = 0.699
we know that log(1000) = 3
3x = 0.699
x = 0.699 / 3
x = 0.233
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