Question

Given log, x = a ,log y = b
(i) write down 10^a-1 in terms
of x
and write down 10^2b in terms of y
​

Answer 1

Step-by-step explanation:

log10 x = a

x = {10}^{a}x=10a

log10 y = b

y = {10}^{b}y=10b

{10}^{a} + 1 = x + 110a+1=x+1

{10}^{2b} = {y}^{2}102b=y2

log10 P=2a-b

log10 P=2log10 x- log10 y

log10 p=log10 x^2-log10 y

hence p=x^2/y

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Answer 2

Answer:

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