Math, asked by singhrishita3456, 5 days ago

Given log2=0.3010 and log3=0.4771 find the value of:log12.5

Answers

Answered by shivanisharan877

0

Answer:

1.0791

Step-by-step explanation:

Given log2=0.3010 and log3=0.4771

log12=log(4×3)

=log4+log3

=log2

2

+log3

=2log2+log3

Substituting the values

=2×0.3010+0.4771

=0.602+0.4771

=1.0791

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